a manufacturing company has 15% cobalt ,25% led and 60% of
copper. if 5kg of led is used in a mixture how much copper we need to use
ans
25%=5kg
100%=20kg
60% of 20 kg= 12kg
A man bought some mangoes at Rs12 per dozen and bought the
same number of at Rs
10 per kg. He sold these mangoes at Rs 13 per dozen and
gained Rs 160.The total
number of mangos
bought by him are
Option
A. 60 dozens
B. 70 dozens
C. 80 dozens
D. 90 dozens
ans
let total no of mangoes is 2x..
then we profit=sp-cp
160=13*2x-(12x+10x)
160=4x
x=40
hence 2x=80
so total no are 80dozens
===============
in a bus left side are 15 seats available,3 few seats in
right side because in rear
exit door .Each seat hold 3 people.In addition ,there is a
seat back can sit 7 people
all together .how many people can sit in a bus?
options:
a)52 b)49 c)95 d)88 e)66 pls explain
ans
Right Side =15 seat
Left Side =15-3 (3 few seat in right side)= 12 seat
Total= 15+12= 27
People can seat in 27 seat= 27*3=81
People can seat in Last Seat = 7
Total People can seat= 81+7=88
Ans= d) 88
Three numbers A,B,Care in ratio 1:2:3. Their average is 600.
If A is increased by
10% and B is increased by 20%, then to get the average
increased by 5%, C will increased by:
a)90
b)100
c)150
d)180
ans
Let be A= x, B=2x, and C=3x.
(x+2x+3x)/3=600
this will be x=300
so, the numbers will be 300,600,900
new average= 105%of 600= 630
Let 110% of 300+80% of 600 + y= 630*3
solve it for y, you will get, y=1080
so, increase in C= 1080-900 =180 ans
=========================
A and B together can complete a work in 12 days. A alone can
complete it in 20 days.
If B does the work
only for half a day daily, then in how many days A and B together
will complete the work?
A. 10 days B. 11 days
C. 15 days D. 20 days
ans
see ,
here given that A and B can do the work in 12 days
so A+B 1 day work = 1/12
unit.................................(1)
also given that , a alone can finish the work in 20 days
therefore
A 1 day work = 1/20 unit........................................(2)
using 1 and 2
we get,
B's 1 day work =1/12 - 1/20
=1/30..............................(3)
---> b can do the complete work in 30 days
now according to statement
if b does the work only half a day then it takes double days
(i.e. 60) to complete the work
so now B 1 day work = 1/60.
also we know
A 1 day work = 1/20
now,
A+B 1 day work = 1/60 + 1/20
= 4/60
= 1/15 unit work
hence ,
A and B together will complete
the work in " 15 DAYS " (answer)
10 women can complete a work in 7 days and 10 children take
14 days to complete the work.
How many days will 5
women and 10 children take to complete the work?
A. 1 B. 3
C. 5 D. 7
ans
5 women's 1 day work=1/14
ans= 1/14 + 1/14
= 1/7 units of work
so 7 days
===============================
15 men take 21 days of 8 hours each to do a piece of work.
How many days of 6 hours each
would 21 women take,
if 3 women do as much work as 2 men ?
ans
15*21*8=2520 man hrs
3w=2men,
1 w=2/3 men,
6d*21*2/3=2520
d=30days
@@@
formula D = M*D*H/M*H
so Days = 15*21*8/14*6 = 30 Days
===========================================
Q. A certain number of bullets were shared by 3 people
equally.Each of them fired 4 bullets
and the sum of the remaining bullets was equal to the
initial share each had got. What was
the initial number of bullets?
Ans
lets each one got x bullets .
so total no of bullets= 3x.
a/c to question each person used 4 bullets each one has
remains with x-4 bullets.
so (x-4)3=x.
x=6.
so total no of bullets =3x =3*6 =18
60 litres of diesel is required to travel 600 km using a 800
cc engine.
If the volume of
diesel required to cover a distance varies directly as
the capacity of the engine, then how many litres of diesel
is required to
travel 800 kms using 1200 cc engine?
Ans
let keep 800 cc constant and calculate amount of diesel for
800 kms.
800*60/600=80 liters.
Now, calculate diesel required for new distance i.e 800 km,
80*1200/800=120 liters.
If a man walks at
rate of 5 kmph, he misses a train by 7 minutes. However, if
he walks at rate of 6
kmph,he reaches the station 5 minutes before the arrival
of train. Find the distance covered by him to reach the
station. [IET] 1)8 km
2)6.5 km 3)6 km 4)7 km
Ans
guys there is a simple frmula for such kind of questions
where time interval matters
(S1*S2)/(S2-S1)* time interval
for example
(6*5)(6-5)*(12/60)
so ans will be 6km .
==============================
Prints a page 64 pg per min .If the printed for 3 hours
except 10 min.Where there
was an paper jam,how
many page did it print
Options:
a)11,700 b)2860 c)11,684
d)12,140 e)10,600
a person travels from his house to office from 11:10am to
11:50 am and covers a distence
of 13.4km. find the average speed of the person.
Ans
time = 11:10 am to 11:50 am = 40 min = 40/60 =2/3 hr
distance = 13.4 km
avg speed = 13.4 /2/3 = 20.3
km/hr
A company has offices in two different buildings. 50% of the
copying machines in the first building and 28% of the copying machines in the
second building received preventive maintenance last
month. If 87% of the company’s copying machines are in the
first building, what percent of all thecopying machines received preventive
maintenance last month?
Ans
50% of 87 machines is 50*87/100=43.5 and
28% of 13 machines is 13*28/100=3.64,
So
43.5+3.64 =47.14
A company organzied a help desk.there have been done 24 hrs
work on software,17 hrs
on help user nd 40% on other services.find the total no. of
hrs have been worked on
that day?
Ans
let total no of hrs = x
they have done 24+17=41
40% of x is 40/100=2/5
x=41+2x/5
x=68.3
A company rented a machine for Rs.700/- a month. Five years
later the treasurer calculated
that if the company
had purchased the machine and paid Rs.100/- monthly maintenance charge,
the company would
have saved Rs.2000/-. What was the purchase price of the machine?
Ans
Let the price of the machine = x rupee
5 year maintenance charge = 100*60 = 6000
so total investment = x+6000
now total rental charges for five year = 700*60 = 42000
so according to given condition
42000-x-6000 = 2000 so x = 34000
A shop sells 17/36 of the total amount of item A, 15/84 of
the total amount of item B,
and 3/504 of the totalamount of item C. The shop buys back
an amount equal to 2/36 of item
A. What total
fraction of items A, B, and C
does the store currently have?
Ans
17 items were sold out of 36 in A,similarly 15 out of 84,3
out of 504,but 2
are returned back in A,so now we have
(15/36)+(15/84)+(3/504) by doing this
we get (210+90+3)/504=303/504.
By selling a product a seller is gaining 10% on selling
price. If he sell that product Rs.80 less,
he would have been losing 10%. What is the cost price?
ans 400
=============
An internet recently hired 8 new
network,in addvertisement 20 network already employed.All new network cam from
university A.In addition 75%of computer addvertisement came from same
university A.what fraction of original 20 network addvertisement came from same
univerity A?
Ans
Answer is
: 13/20
Explanation :
New networks= 8
Already employed networks= 20
Total networks= 28
computer advt. from uni.A= 28*(75/100) =21
out 28 networks 21 came from uni.A
among these 21 we know 8 are newly hired
so 21-8=13 networks among previously employed networks came from uni.A
Answer is : 13/20
Explanation :
New networks= 8
Already employed networks= 20
Total networks= 28
computer advt. from uni.A= 28*(75/100) =21
out 28 networks 21 came from uni.A
among these 21 we know 8 are newly hired
so 21-8=13 networks among previously employed networks came from uni.A
Answer is : 13/20
Foriegn language broadcast records
last 90Mins on each of two sides if it takes 5hrs to translate one hour of
broadcast how long will it take to translate 16 full records??
a)256 b)26 c)48 d)144 e)188
a)256 b)26 c)48 d)144 e)188
Ans
Foriegn language broadcast records
last 90Mins on each of two sides.
so total 3 hr recording in 1 full record.
so 48 hr recording in 16 full records.
it takes 5hrs to translate one hour of broadcast
so it will take 48*5 = 240 hrs to translate 16 full records.
so total 3 hr recording in 1 full record.
so 48 hr recording in 16 full records.
it takes 5hrs to translate one hour of broadcast
so it will take 48*5 = 240 hrs to translate 16 full records.
====================
A word processing program can shift
from one width to another automatically.If a report originally filled 100 lines
,each of which 50 characters wide,how many would be filled where word
processing margin set 40 character per line??
Options:
a) 240 b)50 c)80 d)40 e)125
ans
Options:
a) 240 b)50 c)80 d)40 e)125
ans
50 character per line ...it means
5000 character in 100 lines...
now if 40 character are set per line....to aqqire 5000 characters number of lines reqd would be 5000/40=125.
==================
now if 40 character are set per line....to aqqire 5000 characters number of lines reqd would be 5000/40=125.
==================
As a mean encouraging company
employee to use public transportation,employee is offer a $0.60 per side
discount bus fare. John has spend $30000 per week from monday to friday.How
much cost pay after the discount?
ans
ans
0.60 per
side = 0.60*2 = $1.20 Per day.
1.20 * 5 = $6
30000 - 6 = $ 29994
1.20 * 5 = $6
30000 - 6 = $ 29994
Two merchants sell, each an article
for Rs.1000. If Merchant A computes his profit on cost price, while Merchant B
computes his profit on selling price, they end up making profits of 25%
respectively. By how much is the profit made by Merchant B greater than that of
Merchant A?
Option
A) Rs.66.67
B) Rs. 50
C) Rs.125
D) Rs.200
ans
Option
A) Rs.66.67
B) Rs. 50
C) Rs.125
D) Rs.200
ans
B) 50
profit on cost price = 1000-(100/125)*1000= 200 (selling price-cost price)
profit on selling price = (25/100)*1000 = 250
difference = 50
profit on cost price = 1000-(100/125)*1000= 200 (selling price-cost price)
profit on selling price = (25/100)*1000 = 250
difference = 50
. In a class the average age is
16yrs.if the teacher who is 40 yrs of age is also included ,the average
becomes
17yrs,how many students were there?
ans
becomes
17yrs,how many students were there?
ans
TOTAL= 16X
TOTAL +40 = 17(X+1)
16X +40 = 17(X+1)
X= 23.Ans.
==================
TOTAL +40 = 17(X+1)
16X +40 = 17(X+1)
X= 23.Ans.
==================
5 machines are used for to complete
a work at 10 hrs, 2 of the machine speed increased by 25%. How long it will
take to complete the same works?
ans
each machine got 2hrs to complete
work,so for 100% actual speed time is 2 hrs then..taking 25% in that the work
complete for half an hour...so,there are two machines so one
hour....(reduced)...then the ans will be
9 hrs
================
9 hrs
================
a lawn,grass grows equally thick and uniform
rate every day.It takes 24days for 70 cows
to graze and 60 days for 30 cows.How many cows are required to graze lawn in 96 days.
ans
to graze and 60 days for 30 cows.How many cows are required to graze lawn in 96 days.
ans
20 cows
If C is the amount of grass eaten by one cow every day
and G is amt of grass growing every day,
x is the initial amount of grass, then
x+24G= 70*24*C
x+60G= 30*60*C
solving, G = (10/3)*C
x= 1600C
If n cows are required to graze lawn in 96 days,
1600C+ 96G= 96*n*C
1600C+320C=96nC
n=20 cows
==========================
If C is the amount of grass eaten by one cow every day
and G is amt of grass growing every day,
x is the initial amount of grass, then
x+24G= 70*24*C
x+60G= 30*60*C
solving, G = (10/3)*C
x= 1600C
If n cows are required to graze lawn in 96 days,
1600C+ 96G= 96*n*C
1600C+320C=96nC
n=20 cows
==========================
A person has Rs 100/- in his pocket,
he can as 25 pencils or 15books. He kept 15% of the
money for travelling expenses and purchased 5 pencils.So how many books he can purchase with
the remaining money
ans
money for travelling expenses and purchased 5 pencils.So how many books he can purchase with
the remaining money
ans
price of 1
pencil=100/25=4
price of 1 book= 100/15=20/3
for travelling expenses=rs15(15%of100)
remaining amount=rs85
cost of 5 pencils=4*5=20
now remaining amount=rs65
in 1rs ---------- 3/20 books can purchased
so in rs65 -------- 3/20*65=39/4=9 3/4
so 9 books he can purchase with remaining money
price of 1 book= 100/15=20/3
for travelling expenses=rs15(15%of100)
remaining amount=rs85
cost of 5 pencils=4*5=20
now remaining amount=rs65
in 1rs ---------- 3/20 books can purchased
so in rs65 -------- 3/20*65=39/4=9 3/4
so 9 books he can purchase with remaining money
two sofftware engineers each
programmed 840 lines of code for a paarticular job.The first s/w engineer
programmed 20 lines of code per minute.The second can do 11.5 lines of code.How
many did the 2nd s/w engnr have left to do ?
Ans
for 1st s/w engg.
20 lines -> 1 min
840 lines -> 840/20 = 42 min.
for 2nd engg.
1 min -> 11.5 lines
42 min -> 42 * 11.5 = 483 lines.
840 - 483 = 357 lines are left to do by 2nd engineer.
ans is 357 lines
=====================================
20 lines -> 1 min
840 lines -> 840/20 = 42 min.
for 2nd engg.
1 min -> 11.5 lines
42 min -> 42 * 11.5 = 483 lines.
840 - 483 = 357 lines are left to do by 2nd engineer.
ans is 357 lines
=====================================
driving her car t o work 4days per
week one costs $7.00 aday for parking and 36.00 a week for fuel.how much would
she save week by taking a bus at afuel at a fare fo $1.30 each way?
ans
7*4=$28 & $36 for fuel
tot=28+36=$64
per day by bus=2*1.30=2.60 for week 4*2.60= $10.40
save=$64-$10.40=$53.60
==================
tot=28+36=$64
per day by bus=2*1.30=2.60 for week 4*2.60= $10.40
save=$64-$10.40=$53.60
==================
A person is responsible for Loading
reviews for the games & desktop computers onto a website it takes 30mins to
load a half page review how long will it take to load half page review for ach
of 8 desktop computers
Ans
ans: 30*8=240
240/60=4hrs
240/60=4hrs
as a means of encouraging campany to
use ,an employ public transpoartation ,an employ is offering $10.30 per ride
discount on bus fair.Jon noramlly spend $29.00 per week to reide on the bus to
and from work monday to friday.Hw much will if cost him after the discount
ans
Ans)
Rs.10.41
per week jan spent 29.00rs.Per day jan spent 4.14 rs
for 5 days he spent 20.71 rs.
company discount rs 10.30
after discount 20.71-10.30=10.41rs.
per week jan spent 29.00rs.Per day jan spent 4.14 rs
for 5 days he spent 20.71 rs.
company discount rs 10.30
after discount 20.71-10.30=10.41rs.
A new product cost %0.75 in raw
matr,$4.04 for manufactring and $0.29 to market.if the product is advertised to
sell for $5.10,how much units must be added to provide a net profit of $5600?
Ans
1 product total cost = .75+4.04+.29
= $5.08
s.p. = $5.10
profit of selling of 1 product = $0.02
number of products to gain profit of $5600 = 5600/.02 = 280000
answer 280000)
======================================================
s.p. = $5.10
profit of selling of 1 product = $0.02
number of products to gain profit of $5600 = 5600/.02 = 280000
answer 280000)
======================================================
kevin board the bus at 9:36 am,and
if travel the 35.4 km distance to his office by 10:16am.what is the average
speed of the bus during his entire journey?
a 70.8 km.hr b 35.4km/hr c 106.2 km/hr d 108.2 km.hr
a 70.8 km.hr b 35.4km/hr c 106.2 km/hr d 108.2 km.hr
Ans
9:36to 10:16 = 40min that is 2/3hr
Distance = 35.4/(2/3)= 53.1km/hr
Distance = 35.4/(2/3)= 53.1km/hr
0r
time = 40/60= 2/3
dis= 35.4
same dis so, avg speed= 2*dis/t
= 2*35.4/(2/3)
=106.2 km/hr
================
dis= 35.4
same dis so, avg speed= 2*dis/t
= 2*35.4/(2/3)
=106.2 km/hr
================
The number of calls coming into a
call center on Tuesday are 5/11 more than 1/4 the number that came in on
Monday. The total number of calls for the two days together was 270. How many
calls came in on Tuesday?
a) 50
b) 61
c) 20
d) 72
e) 18
a) 50
b) 61
c) 20
d) 72
e) 18
Ans
The regular longer method is framing
the equations and solving those equations.
If we take the number of calls on Monday as x, the number of calls on Tuesday are
¼ x + 5/11 * ¼ x
=1/4 x + 5/44 x
= 16/ 44 x
The total number of calls on two days is 270
X + 16/44 x = 270
60/44 x = 270
Solving x we gat x as 198.
The number of calls on Monday is 198, which implies the number of calls on Tuesday is 72
72 is the answer.
==============
If we take the number of calls on Monday as x, the number of calls on Tuesday are
¼ x + 5/11 * ¼ x
=1/4 x + 5/44 x
= 16/ 44 x
The total number of calls on two days is 270
X + 16/44 x = 270
60/44 x = 270
Solving x we gat x as 198.
The number of calls on Monday is 198, which implies the number of calls on Tuesday is 72
72 is the answer.
==============
Computer chip cost 25$ each, plus a
license fee of 775$ per year. If a company spends 75775$ over on computer chips
over a three year period, How many chips did it buy?
2935
2938
3000
3031
25258
solution cost of 1 chip 25
therefore 25x + (775*3) = 75775
x = 2938
===============
2935
2938
3000
3031
25258
solution cost of 1 chip 25
therefore 25x + (775*3) = 75775
x = 2938
===============
If a certain computer is capable of
printing 3900 monthly credit card bills per hour, while a new model is capable
of printing at a rate of 6300 per hour, the old model will take approximately
how much longer than the new model to print 10300 bills?
a) 97
b) 258
c) 60
d) 106
e) 14
ans
a) 97
b) 258
c) 60
d) 106
e) 14
ans
the old
computer will print 10300 bills in 10300/3900 hours = 103/39
the new computer will print 10300 bills in 6300/10300 hours = 103/63
the time difference is 103/39 - 103/63 = (6489 - 4017) / 39*63 = 2472/2457 = 1 hour = 60 minutes
the answer is c) 60
the new computer will print 10300 bills in 6300/10300 hours = 103/63
the time difference is 103/39 - 103/63 = (6489 - 4017) / 39*63 = 2472/2457 = 1 hour = 60 minutes
the answer is c) 60
Find the cash required to purchase Rs. 1600, 17/2 %
stock at 105. (Brokerage 1/2%)
Ans
for 100 stock it required cash is
105+1/2
because 1/2 is brokerage it is added to because of purchasing.
so 100 stock purchased cash required is 105.5
1600 stock purchased cash required is 1600*(105.5/100)=1688
===============================
because 1/2 is brokerage it is added to because of purchasing.
so 100 stock purchased cash required is 105.5
1600 stock purchased cash required is 1600*(105.5/100)=1688
===============================
36 identical chairs must be arranged
in rows with the same number of chairs in each row. Each row must contain at
least three chairs and there must be at least three rows. The row is parallel
to the front of the room. How many different arrangements are possible? Pick
one of the choices
a) 2 b) 4 c) 5 d)6 e) 10
a) 2 b) 4 c) 5 d)6 e) 10
Ans
(3,12),(4,9),(6,6)(9,4),(12,3)
no of diff. arrangement=5
no of diff. arrangement=5
A pension fund has a total of $1 million invested in stock of the ABC company and the bonds of the DEE Corporation. The ABC stocks yields 12% in cash each year, and the DEE bonds pay 10% in cash each year. The pension fund received a total of $115,000 in cash from ABC stock and the DEE bonds last year. How much money was invested in ABC stock?
a)$750,000 b)$600,000 c)$500,000 d)$333,333.33 e)$250,000
Ans.
s+b=1000000----1 (1 million=1000000)
.12s+.1b=115000----2
solving 1 and 2,we get s=750,000 (a) is correct ans.
==========================
.12s+.1b=115000----2
solving 1 and 2,we get s=750,000 (a) is correct ans.
==========================
Today 1999, the age of Mohan and his
grandmother differ by 6 years. Before 50 years Grandmother age was twice as
that of Mohan. What is the present age of Mohan?
ans
ans
Let before 50 year grandmother's age
2x then mohan's age was x
So now (2x+50)-(x+50)=6
X=6 year
So present age of mohan=6+50=56 year
=============================
So now (2x+50)-(x+50)=6
X=6 year
So present age of mohan=6+50=56 year
=============================
In 1930 the father's age is 8 times
of son's age. in 1938 father's age is 10 times of son's age in 1930. in 1940
what is their age's
Ans
In 1930 f=8s; In 1938 I.e 8 years
after f+8=10*s;
8s+8=10s=>s=4
Therefore f=8*4=32 in 1930;
In 1940 I.e after 10 years f=42,s=14
8s+8=10s=>s=4
Therefore f=8*4=32 in 1930;
In 1940 I.e after 10 years f=42,s=14
===================================================
Nikhil spent 45% of his monthly
stipend on food and transport. 20% of the
remaining on book and half of the remaining on the other expenses. If he is left
with Rs.880 now, how much is his monthly stipend
Ans.
remaining on book and half of the remaining on the other expenses. If he is left
with Rs.880 now, how much is his monthly stipend
Ans.
let X be the monthly stipent....
then
(1/2)*80%*55%*X= 880
X= rs. 4000
===============
(1/2)*80%*55%*X= 880
X= rs. 4000
===============
A watch was sold at a profit of 15%.
If its cost had been 5% less and it had been sold for Rs. 21 less, than the profit
would have been 10%. Find the cost price of the watch
ans
ans
So let cost price =100
then 1st selling price =115(profit 15%)
the second cost price =95(cost price is 5% less)
then second price =95+10% of 95=104.50
therefore the difference in selling price =115-104.50=10.50
bt actual difference is 21
if difference is 10.50 the cost price=100
if difference is 21 the cost price =(100/10.50)*21=200
so x =200 (answer)
===========================================================
then 1st selling price =115(profit 15%)
the second cost price =95(cost price is 5% less)
then second price =95+10% of 95=104.50
therefore the difference in selling price =115-104.50=10.50
bt actual difference is 21
if difference is 10.50 the cost price=100
if difference is 21 the cost price =(100/10.50)*21=200
so x =200 (answer)
===========================================================
A boatman goes 2 km against the
current of the stream in 1 hour and goes 1 km along the current in 10 minutes.
How long will it take to go 5 km in stationary water?
A. 40 minutes B. 1 hour
C. 1 hr 15 min D. 1 hr 30 min
ans
A. 40 minutes B. 1 hour
C. 1 hr 15 min D. 1 hr 30 min
ans
upstream speed = 2km/h
downstream speed = 6km/h
speed in still water = 1/2(6+2) = 4km/h
so to cover 5 km 75 minutes or 1h15m requires.
=============
downstream speed = 6km/h
speed in still water = 1/2(6+2) = 4km/h
so to cover 5 km 75 minutes or 1h15m requires.
=============
There are 9 popsicles: 3 orange,
3 cherry, 3 grape. There are 4 children. What is the
probability
that all 4 children will get the flavor of their choice?
Ans
Consider the 4 children. Each of
them has a flavor preference, and so
there are 3x3x3x3 = 81 possibilities for what the kids want (we assume
that each kid does in fact want one of the three flavors: orange,
cherry, or grape).
Of these 81 possibilities, 3 of them mean that one child will be
unhappy: OOOO, CCCC, and GGGG (i.e., when all four of them want the
same flavor as the others). For all of the other possibilities (e.g.
OOCG, OOOC, OOCC,...) there are going to be enough popsicles of the
required flavors.
Assuming that each of the 81 possibilities is equally likely,
Pr(4 happy kids) = 1 - Pr(at least one unhappy kid)
= 1 - 3/81
= 1 - 1/27
= 26/27
=============
there are 3x3x3x3 = 81 possibilities for what the kids want (we assume
that each kid does in fact want one of the three flavors: orange,
cherry, or grape).
Of these 81 possibilities, 3 of them mean that one child will be
unhappy: OOOO, CCCC, and GGGG (i.e., when all four of them want the
same flavor as the others). For all of the other possibilities (e.g.
OOCG, OOOC, OOCC,...) there are going to be enough popsicles of the
required flavors.
Assuming that each of the 81 possibilities is equally likely,
Pr(4 happy kids) = 1 - Pr(at least one unhappy kid)
= 1 - 3/81
= 1 - 1/27
= 26/27
=============
A jar contains 2 red, 3 blue, and 4
green marbles. Niki draws one marble from the jar, and then Tom draws a marble.
What is the probability that Niki will draw a green marble and Tom will draw a
blue marble?
Ans
4/9 * 3/8 = 1/6
A person can buy 50 cds with $135
and 15 dvds with $100 nikitha has a budjet of $1680 for
cds & budget of $150 for dvds
How
many cds & dvds in total can she buy?
Ans
cds--(50*1680)/135=622 apprx
dvds--(150*15)/100=22 apprx
in total=644 apprx
================================
dvds--(150*15)/100=22 apprx
in total=644 apprx
================================
A father of 6 children takes 2 of
his children at a time to a circus as often as he can, without
taking the same pair of children
together more than once. How many times does the father go to
the
circus?
Ans
He has to choose 2 children from 6
total number of combinations=6c2=15
Father goes to circus 15 times
===================================
A set of 7 pens, 9 erasers and 11
sharpeners costs Rs 79 and 2 pens, 5 erasers and 8
sharpeners cost Rs 42. Find the total cost of one
sharpeners, one eraser and one pen.
Ans
7P+9E+11s=79 ---1
2P+5E+8S=42---2
eliminating P.... eq1 *2 - eq2*7 , gives
17E+34S=136 ----3
eliminaing S ....eq1*8-eq2*11, gives
34P+17E=170 ----4
adding eq3 and eq4,
34P+34E+34S=306
P+E+S=9
========================
2P+5E+8S=42---2
eliminating P.... eq1 *2 - eq2*7 , gives
17E+34S=136 ----3
eliminaing S ....eq1*8-eq2*11, gives
34P+17E=170 ----4
adding eq3 and eq4,
34P+34E+34S=306
P+E+S=9
========================
8 chairs are numbered from 1 to 8.
Two women first choose two chairs from those marked 1 to 4 and 3 men selects 3
chairs from the remaining. Find the number of possible arrangements
ans
1,2,3,4,5,6,7,8
are 8 chairs.
two women first choose two chairs from 1,2,3,4
in 4p2 ways = 12 different ways
3 men selects 3 chairs from the rest 6 chairs = 6p3 = 6*5*4 = 120.
Total number of possible arrangement = 12*120 = 1440.
two women first choose two chairs from 1,2,3,4
in 4p2 ways = 12 different ways
3 men selects 3 chairs from the rest 6 chairs = 6p3 = 6*5*4 = 120.
Total number of possible arrangement = 12*120 = 1440.
a company decided to install a
fountain within it main entrance lobby.if fountain is to be 148
cm wide 297 long and 91 cm
deep,how much water would be required to feel the fountain to a
depth of 69cm?(1liter=1000 cubic centimeters)
ans
we may do it like this
148*297*69/1000
=3033 liters
===================
148*297*69/1000
=3033 liters
===================
a container of production line
solvent is mixed at 22% strength and another is mixed at 53%
strength.to obtain 12 liter of a
mixture that is 25% strength,how many liter should be used from
the
container that is mixed at 53% strength?
Ans
ans 1 5/31
simply use the shortcut link up process for finding the ratio.
22 53
25
(53-25) (25-22)
28 3
so the ratio should be 28:3
so 53% strength solvent is 12*3/31
36/31
==============
simply use the shortcut link up process for finding the ratio.
22 53
25
(53-25) (25-22)
28 3
so the ratio should be 28:3
so 53% strength solvent is 12*3/31
36/31
==============
IN a lawn,grass grows equally thick
and uniform rate every day.It takes 24days for 70 cows to graze and 60 days for
30 cows.How many cows are required to graze lawn in 96 days.
Ans
20 cows
If C is the amount of grass eaten by one cow every day
and G is amt of grass growing every day,
x is the initial amount of grass, then
x+24G= 70*24*C
x+60G= 30*60*C
solving, G = (10/3)*C
x= 1600C
If n cows are required to graze lawn in 96 days,
1600C+ 96G= 96*n*C
1600C+320C=96nC
n=20 cows
========================
If C is the amount of grass eaten by one cow every day
and G is amt of grass growing every day,
x is the initial amount of grass, then
x+24G= 70*24*C
x+60G= 30*60*C
solving, G = (10/3)*C
x= 1600C
If n cows are required to graze lawn in 96 days,
1600C+ 96G= 96*n*C
1600C+320C=96nC
n=20 cows
========================
What
sum of money will accumulate to Rs.5300 at 8% rate of interest in 9 months?
Ans 5000
The printed price on a book is
400, a bookseller offers a 10% discount on it. If he still earns a
profit of 12&, the CP of the
book is
a) 280
b) 352
c) 360
d) 300
ans
S.P= 360 Rs.
If Profit = 12% then 1.12*C.P = S.P
1.12*C.P = 360
C.P= 321.43 Rs.
And If Profit=12 Rs. then C.P= 348 RS.
As there is ambiguity in question.
=========================================
If Profit = 12% then 1.12*C.P = S.P
1.12*C.P = 360
C.P= 321.43 Rs.
And If Profit=12 Rs. then C.P= 348 RS.
As there is ambiguity in question.
=========================================
17)A thing cost $500,the amount
is decreased by 20%,then how much less must be paid?
ANS:
100$
Price after 20%
decrease=500-(500*20/100)=400
Amount less to be paid=500-400=100
==
Thankyou..
ReplyDelete